Integrand size = 23, antiderivative size = 87 \[ \int \frac {1}{\left (a+b x^3\right )^{3/4} \left (c+d x^3\right )^{7/12}} \, dx=\frac {x \left (\frac {c \left (a+b x^3\right )}{a \left (c+d x^3\right )}\right )^{3/4} \left (c+d x^3\right )^{5/12} \operatorname {Hypergeometric2F1}\left (\frac {1}{3},\frac {3}{4},\frac {4}{3},-\frac {(b c-a d) x^3}{a \left (c+d x^3\right )}\right )}{c \left (a+b x^3\right )^{3/4}} \]
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Time = 0.01 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.043, Rules used = {388} \[ \int \frac {1}{\left (a+b x^3\right )^{3/4} \left (c+d x^3\right )^{7/12}} \, dx=\frac {x \left (c+d x^3\right )^{5/12} \left (\frac {c \left (a+b x^3\right )}{a \left (c+d x^3\right )}\right )^{3/4} \operatorname {Hypergeometric2F1}\left (\frac {1}{3},\frac {3}{4},\frac {4}{3},-\frac {(b c-a d) x^3}{a \left (d x^3+c\right )}\right )}{c \left (a+b x^3\right )^{3/4}} \]
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Rule 388
Rubi steps \begin{align*} \text {integral}& = \frac {x \left (\frac {c \left (a+b x^3\right )}{a \left (c+d x^3\right )}\right )^{3/4} \left (c+d x^3\right )^{5/12} \, _2F_1\left (\frac {1}{3},\frac {3}{4};\frac {4}{3};-\frac {(b c-a d) x^3}{a \left (c+d x^3\right )}\right )}{c \left (a+b x^3\right )^{3/4}} \\ \end{align*}
Time = 5.62 (sec) , antiderivative size = 86, normalized size of antiderivative = 0.99 \[ \int \frac {1}{\left (a+b x^3\right )^{3/4} \left (c+d x^3\right )^{7/12}} \, dx=\frac {x \left (1+\frac {b x^3}{a}\right )^{3/4} \sqrt [4]{1+\frac {d x^3}{c}} \operatorname {Hypergeometric2F1}\left (\frac {1}{3},\frac {3}{4},\frac {4}{3},\frac {(-b c+a d) x^3}{a \left (c+d x^3\right )}\right )}{\left (a+b x^3\right )^{3/4} \left (c+d x^3\right )^{7/12}} \]
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\[\int \frac {1}{\left (b \,x^{3}+a \right )^{\frac {3}{4}} \left (d \,x^{3}+c \right )^{\frac {7}{12}}}d x\]
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\[ \int \frac {1}{\left (a+b x^3\right )^{3/4} \left (c+d x^3\right )^{7/12}} \, dx=\int { \frac {1}{{\left (b x^{3} + a\right )}^{\frac {3}{4}} {\left (d x^{3} + c\right )}^{\frac {7}{12}}} \,d x } \]
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\[ \int \frac {1}{\left (a+b x^3\right )^{3/4} \left (c+d x^3\right )^{7/12}} \, dx=\int \frac {1}{\left (a + b x^{3}\right )^{\frac {3}{4}} \left (c + d x^{3}\right )^{\frac {7}{12}}}\, dx \]
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\[ \int \frac {1}{\left (a+b x^3\right )^{3/4} \left (c+d x^3\right )^{7/12}} \, dx=\int { \frac {1}{{\left (b x^{3} + a\right )}^{\frac {3}{4}} {\left (d x^{3} + c\right )}^{\frac {7}{12}}} \,d x } \]
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\[ \int \frac {1}{\left (a+b x^3\right )^{3/4} \left (c+d x^3\right )^{7/12}} \, dx=\int { \frac {1}{{\left (b x^{3} + a\right )}^{\frac {3}{4}} {\left (d x^{3} + c\right )}^{\frac {7}{12}}} \,d x } \]
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Timed out. \[ \int \frac {1}{\left (a+b x^3\right )^{3/4} \left (c+d x^3\right )^{7/12}} \, dx=\int \frac {1}{{\left (b\,x^3+a\right )}^{3/4}\,{\left (d\,x^3+c\right )}^{7/12}} \,d x \]
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